URI / BEE CROWD 1078 - Multiplication Table Solution in C,C++,Python | URI - BEECROWD - BEE 1078 Solution in C,C++,Python

                                                                                            beecrowd | 1078

Multiplication Table

Adapted by Neilor Tonin, URI  Brazil

                                                                                             Timelimit: 1

Read an integer N (2 < N < 1000). Print the multiplication table of N.
1 x N = N      2 x N = 2N        ...       10 x N = 10N  

Input

The input is an integer N (1 < N < 1000).

Output

Print the multiplication table of N., like the following example.

Input Sample	Output Sample
140	1 x 140 = 140 2 x 140 = 280 3 x 140 = 420 4 x 140 = 560 5 x 140 = 700 6 x 140 = 840 7 x 140 = 980 8 x 140 = 1120 9 x 140 = 1260 10 x 140 = 1400

URI / BEE CROWD 1078 - Multiplication Table Solution in C,C++,Python | URI - BEECROWD - BEE 1078 Solution in C,C++,Python

                                     Demonstration:

Here, the user input is stored in the int variable n. Then, we use a for loop to print the multiplication table up to 10. Then, the loop runs from i = 1 to i = 10. In each iteration of the loop, i * n is printed.

Finally, print the result. 

N.B: Don't copy paste the code as same. Just try to understand it and try yourself.

  URI / BEE 1078 Solution in C :   

URI / BEECROWD Online Judge 1078 Solve  in C :

#include<stdio.h>

int main()
{
    int i,n;
    scanf("%d",&n);
    for(i=1;i<=10;i++){
        printf("%d x %d = %d\n",i,n,i*n);
    }
}

  URI / BEE 1078 Solution in C++ :   

URI / BEECROWD Online Judge 1078 Solve  in C++ :

#include <iostream>

using namespace std;

int main(){
    int N;
    
    cin >> N;
    
    for(int i = 1; i <= 10; i++)
            cout << i << " x " << N << " = " << N*i << "\n";
            
    return 0;
}

  URI / BEE 1078 Solution in Python :   

URI / BEECROWD Online Judge 1078 Solve  in Python :

n=int(input())
for i in range(1,11):
    print(f"{i} x {n} = {i*n}")

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