URI - BEECROWD - BEE 1051 - Taxes Solution in C,C++,Python | URI - BEECROWD - BEE Online Judge Solution 1051 - Taxes
In an imaginary country called Lisarb, all the people are very happy to pay their taxes because they know that doesn’t exist corrupt politicians and the taxes are used to benefit the population, without any misappropriation. The currency of this country is Rombus, whose symbol is R$.
Read a value with 2 digits after the decimal point, equivalent to the salary of a Lisarb inhabitant. Then print the due value that this person must pay of taxes, according to the table below.
Remember, if the salary is R$ 3,002.00 for example, the rate of 8% is only over R$ 1,000.00, because the salary from R$ 0.00 to R$ 2,000.00 is tax free. In the follow example, the total rate is 8% over R$ 1000.00 + 18% over R$ 2.00, resulting in R$ 80.36 at all. The answer must be printed with 2 digits after the decimal point.
Input
The input contains only a float-point number, with 2 digits after the decimal point.
Output
Print the message "R$" followed by a blank space and the total tax to be payed, with two digits after the decimal point. If the value is up to 2000, print the message "Isento".
Input Samples | Outputs Samples |
3002.00 | R$ 80.36 |
1701.12 | Isento |
4520.00 | R$ 355.60 |
URI Online Judge Solution 1051 - Taxes | URI 1051 Solution in C,C++,Python :
Demonstration:
It's a not a hard problem.You just have to check the conditions by using if-else to find the combination of the table given.Then you have to print those values according to the problem's statement.
A percentage is a fraction whose denominator (bottom) is 100.
So if we say 50%, we mean 50/100 = 1/2 (after cancelling).
So 50% means ½. If want to find 10% of something, 'of' just means 'times'.
So 10% of 150 = 10/100 × 150 = 15.
If you have to turn a percentage into a decimal, just divide by 100.
For example, 25% = 25/100 = 0.25.
To change a decimal into a percentage, multiply by 100. So 0.3 = 0.3 × 100 =30% .
Example:
Find 25% of 10 (remember 'of' means 'times').
25/100 × 10
= 2.5
#include <stdio.h>
int main(){
double sal;
scanf("%lf", &sal);
if(sal <= 2000.00){
printf("Isento\n");
}else if (sal >= 2000.01 && sal <= 3000.00){
printf("R$ %.2f\n", (sal - 2000.00)*0.08);
}else if (sal >= 3000.01 && sal <= 4500.00){
printf("R$ %.2f\n", ((sal - 3000.00)*0.18 + 1000.00*0.08));
}else if (sal >= 4500.01){
printf("R$ %.2f\n", ((sal - 4500.00)*0.28 + 1500.00*0.18 + 1000.00*0.08));
}
return 0;
}
#include
ReplyDelete#include
using namespace std;
int main() {
int input;
string months[12] ={"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
cin >> input;
for(int i = 0 ; i<12 ; i ++)
{
if (i + 1 == input)
cout << months[i]<<endl;
}
return 0;
}